kiyondinewton02
contestada

determine the empirical formula of the compound formed when 1.2g of magnesium reacts with 3.55g of chlorine.take the molar mass of magnesium and chlorine to be 24g and 35.5g.​

Respuesta :

rspill6

Answer:  MgCl2

Explanation:

Convert the masses of Mg and Cl to moles:

Mg:  1.2g/24g/mole = 0.050 moles

Cl:    3.55g/35.5g/mole = 0.100 moles

The ratio of Cl to Mg is 2 to 1:  (0.100 moles Cl/0.050 moles Mg),  Therefore there must be 2 Cl for every Mg:

MgCl2

This is the empirical formula since all we know is the ratio.  If could also be Mg2Cl4, Mg3Cl6, etc,  [i.e., (MgCl2)n]