Answer:
Range is 62.5 metres
Explanation:
Time of flight
[tex]t = \frac{2u \sin( \theta) }{g} [/tex]
for range, acceleration is zero
from second newton's equation:
[tex]S = ut + \frac{1}{2} {at}^{2} [/tex]
but a = 0:
let range be x:
[tex]x = ut \\ x = \frac{2 {u}^{2} \sin( \theta) }{g} \\ \\ x = \frac{ \{2 \times 25 {}^{2} \sin(30 \degree) \}}{10} \\ \\ x = 62.5 \: metres[/tex]
[ taken g to be 10 m/s² ]
