Answer:
[tex]14\text{ liters}[/tex]
Step-by-step explanation:
Let the total amount of water the container can hold be [tex]t[/tex]. Currently, there are [tex]n[/tex] liters in the container. If Ito adds 10 liters of water, the container will be 60% full. We can express this statement in the following mathematical equation:
[tex]n+10=0.6t[/tex]
Next, we're given that if we add 6 more liters to this, the container will be 75% full.
Therefore, we have:
[tex]n+10+6=0.75t,\\n+16=0.75t[/tex]
This is a system of equations:
[tex]\begin{cases}n+10=0.6t,\\ n+16=0.75t\end{cases}[/tex]
Subtract both equations to conveniently get rid of [tex]n[/tex]:
[tex]10-16=0.6t-0.75t,[/tex]
Combine like terms:
[tex]-6=-0.15t[/tex]
Divide both sides by -0.15:
[tex]t=\frac{-6}{-0.15}=40[/tex]
Now substitute [tex]t=40[/tex] into any equation (I'll choose the first):
[tex]n+10=0.6(40),\\n+10=24[/tex]
Subtract 10 from both sides:
[tex]n=24-10=\boxed{14\text{ liters}}[/tex]
