umaizahussain
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A 6.0 kg mass is placed on a 20º incline which has a coefficient of friction of 0.15. What is the acceleration of the mass down the incline? show all work please​

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Luv2Teach

Answer:

Explanation:

The form of Newton's 2nd Law that we use for this is:

F - f = ma where F is the Force pulling the mass down the ramp forward, f is the friction trying to keep it from moving forward, m is the mass and a is the acceleration (and our unknown).

We know mass and we can find f, but we don't have F. But we can solve for that by rewriting our main equation to reflect F:

[tex]wsin\theta-\mu F_n=ma[/tex] That's everything we need.

w is weight: 6.0(9.8). Filling in:

6.0(9.8)sin20 - .15(6.0)(9.8) = 6.0a and

2.0 × 10¹ - 8.8 = 6.0a and

11 = 6.0a so

a = 1.8 m/s/s

pstnonsonjoku

From the description of the question, the acceleration is 1.95 ms-2.

What is friction?

The term friction is defined a the force that seeks to prevent the movement of a surface on another.

Now we know that;

ma =mgsinθ -  ukmgcosθ

ma =( 6 * 9.8 * sin 20) - ( 0.15 * 6 * 9.8 * cos 20)

a =  ( 6 * 9.8 * sin 20) - ( 0.15 * 6 * 9.8 * cos 20) /6

a = 20 - 8.29/6

a = 1.95 ms-2

Learn more about acceleration: https://brainly.com/question/14356798