Answer:
[tex]{ \tt{ \frac{4 {x}^{5} }{2 {x}^{2} + 5 } = 59 }}[/tex]
Cross multiply the variables:
[tex]{ \tt{4 {x}^{5} = 59(2 {x}^{2} + 5)}} \\ { \tt{4 {x}^{5} = 118 {x}^{2} + 295}} \\ { \tt{4 {x}^{5} - 118 {x}^{2} = 295}}[/tex]
Factorise the equation:
[tex]{ \tt{ {x}^{2}(4 {x}^{3} - 118) = 295 }}[/tex]
Either x² or ( 4x³ - 118 ) is equal to 295:
For x²:
[tex]{ \tt{ {x}^{2} = 295}} \\ { \tt{first \: answer : \: x =17.2 }}[/tex]
For ( 4x³ - 118 ):
[tex]{ \tt{4 {x}^{3} = 413 }} \\ { \tt{ {x}^{3} = 103.25}} \\ { \tt{second \: answer : \: x = 4.7 }}[/tex]
