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Answer:
√5 +√6
Step-by-step explanation:
We know that the square of a binomial is ...
(a +b)^2 = a^2 +2ab +b^2
Then the square root of it is ...
a + b = √(a^2 +b^2 +2ab)
Using a=√x and b=√y, this is ...
√x +√y = √(x + y + 2√(xy))
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For the given expression, we need to find x and y such that ...
xy = 30 and x+y = 11
Using x=5, y=6, we meet those requirements.
[tex]\displaystyle \sqrt{11+2\sqrt{30}}=\sqrt{5+6+2\sqrt{5\cdot6}}=\boxed{\sqrt{5}+\sqrt{6}}[/tex]
