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3. Divide the following polynomials using the long division model: (4x^4 - 5x^2 + 2x^2 - X+5) = (x^2 + x+1).

Part I: Express this problem using the standard format for a problem of dividend - divisor divisor) dividend (2 points)

Part II: Use this checklist to proceed through this problem: (8 points)

• How many times does x2 go into the largest term in the problem?
* write the value on top of the problem and multiply that value by x^+x+1
*write the product below the lowest line on your work and subtract if from what reminds in the problem
*continue this process until you fab no longer divide x^2 into what reminds in the problem
*include your remainder in the final answer ​

Respuesta :

Answer:

[tex]\dfrac{4 \cdot x^4 - 5\cdot x^3 + 2 \cdot x^2 - x + 5}{x^2 + x + 1} = 2 \cdot x^2 - 9 \cdot x + 7 \ Remainder \ (x - 2)[/tex]

Step-by-step explanation:

Part I

The problem can be expressed as follows;

The dividend is 4·x⁴ - 5·x³ + 2·x² - x + 5

The divisor is x² + x + 1

[tex]\dfrac{4 \cdot x^4 - 5\cdot x^3 + 2 \cdot x^2 - x + 5}{x^2 + x + 1}[/tex]

Part II

The number of times x² goes into the larest term, 4·x⁴ = 4·x² times

2·x² - 9·x + 7

[tex]\dfrac{4 \cdot x^4 - 5\cdot x^3 + 2 \cdot x^2 - x + 5}{x^2 + x + 1}[/tex]

4·x⁴ + 4·x³ + 4·x²

-9·x³ - 2·x² - x + 5

-9·x³ - 9·x² - 9·x

7·x² + 8·x + 5

7·x² + 7·x + 7

x - 2

Therefore, we have;

[tex]\dfrac{4 \cdot x^4 - 5\cdot x^3 + 2 \cdot x^2 - x + 5}{x^2 + x + 1} = 2 \cdot x^2 - 9 \cdot x + 7 \ Remainder \ (x - 2)[/tex]

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