Answer:
[tex]-\frac{3p^8}{4q^3}[/tex]
Step-by-step explanation:
One is given the following expression,
[tex]\frac{15p^-^4q^-^6}{-20p^-^1^2q^-^3}[/tex]
Since (15) and (-20) are both divisible by (5), one can divide both terms by (5) to simplify it.
[tex]\frac{3p^-^4q^-^6}{-4p^-^1^2q^-^3}[/tex]
Now bring all of the terms with a negative exponent to the numerator. Multiply the exponents by (-1), then add them to the exponents of the like term in the numerator. Simplify the resulting exponents
[tex]\frac{3p^-^4q^-^6}{-4p^-^1^2q^-^3}[/tex]
[tex]\frac{3p^-^4^+^(^-^1^)^(^-^1^2^)q^-^6^+^(^-^1^)^(^-^3^)}{-4}[/tex]
[tex]\frac{3p^-^4^+^1^2q^-^6^+^3}{-4}[/tex]
[tex]\frac{3p^8q^-^3}{-4}[/tex]
Rewrite the fraction such that there are no negative exponents. Remember the rule, when bringing a number from the numerator to the denominator and back, multiply the exponent of the number by (-1). One can only switch numbers between the numerator and the denominator when all operations are multiplication or division.
[tex]\frac{3p^8q^-^3}{-4}[/tex]
[tex]-\frac{3p^8}{4q^3}[/tex]
