16-07-2021
Mathematics

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[tex]\sqrt{x^{2} +2x+2\\}[/tex]

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Аноним Аноним

16-07-2021

Answer:

[tex]{ \tt{ \sqrt{ {x}^{2} } + 2x + 2}} \\ { \tt{ = x + 2x + 2}} \\ = { \tt{3x + 2}}[/tex]

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