Answer:
The right solution is "24.39 per sec".
Explanation:
According to the question,
⇒ [tex]v=\frac{502.1}{\sqrt{3} }[/tex]
[tex]=289.9 \ m/s[/tex]
The time will be:
⇒ [tex]t=\frac{d}{v}[/tex]
[tex]=\frac{2\times 6}{289.9}[/tex]
[tex]=\frac{12}{289.9}[/tex]
[tex]=0.041 \ sec[/tex]
hence,
⇒ [tex]N=\frac{1}{t}[/tex]
[tex]=\frac{1}{0.041}[/tex]
[tex]=24.39 \ per \ sec[/tex]
