contestada

Consider the line y=8x - 3

Find the equation of the line that is parallel to this line and passes through the point (3, -2)

Find the equation of the line that is perpendicular to this line and passes through the point (3, -2)

Respuesta :

lesliewang964

Answer:

y=8x-26

y=-1/8x-13/8

Step-by-step explanation:

Y=kx+b

When the two lines are parallel,

k1=k2

k2=8 And passes through the point (3, -2)

So y+2=8(x-3)

Get the answer y=8x-26

When the two lines are perpendicular,

k1*k2=-1

K2=-1/8 And passes through the point (3,-2)

So y+2=-1/8（x-3）

Get the answer y=-1/8x-13/8

Otras preguntas