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What amount of oxygen gas is needed to produce 2.85 mol of chlorine gas……
NEED HELP ASAP!
A) 0.95 mol
B) 1.90 mol
C) 2.85 mol
D) 5.70 mol
E) 8.55 mol

What amount of oxygen gas is needed to produce 285 mol of chlorine gas NEED HELP ASAP A 095 mol B 190 mol C 285 mol D 570 mol E 855 mol class=

Respuesta :

Answer:

B

Explanation:

2,85/3=0,95

Balanced Equation:-

SeCl₆ + O₂ ⇒SeO₂ + 3Cl2

From the balanced equation, 3 moles of Cl₂ are produced from 1 mole of O₂ on reaction with SeCl₆.

Therefore, 2.85 mol of Cl₂ are produced from (1/3) x 2.85 = 0.95 mole of O₂ on reaction with SeCl₆.

Hence, the amount of O₂ required = 0.95 mole.

What is a Balanced Equation?

A balanced equation is an equation for a chemical reaction in which the number of atoms for each element in the reaction and the total charge is the same for both the reactants and the products. In other words, the mass and the charge are balanced on both sides of the reaction.  In this chemical reaction, nitrogen (N₂) reacts with hydrogen (H) to produce ammonia (NH₃). The reactants are nitrogen and hydrogen, and the product is ammonia.

Therefore, (A) 0.95 mol option is the correct answer.

To learn more about Balanced Equation, refer here :

https://brainly.com/question/11904811

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