Respuesta :

Answer:

C) [tex]sin\theta+cos\theta[/tex]

Step-by-step explanation:

[tex](sin^2\theta+cos^2\theta)(sin\theta+cos\theta)[/tex]

[tex]sin\theta+cos\theta[/tex]

Recall the Pythagorean Trigonometric Identity where [tex]sin^2\theta+cos^2\theta=1[/tex], so [tex]1(sin\theta+cos\theta)=sin\theta+cos\theta[/tex]

Answer:

C

Step-by-step explanation:

To start this problem off, we should know an important trig rule:

[tex]\sin^2(\theta)+\cos^2(\theta)=1[/tex]

From here, it is simple:

[tex](\sin^2(\theta)+\cos^2(\theta))(\sin(\theta)+\cos(\theta))=\\1(\sin(\theta)+\cos(\theta))=\\\sin(\theta)+\cos(\theta)[/tex]

C

I hope this helps! Let me know if you have any questions :)