Answer:
The answer is "[tex]55.05 \ \frac{J}{K}[/tex]"
Explanation:
Given value:
[tex]Q_m=4.184 \times 10^3 \ J\\T_0=100^{\circ}\\T_1=24^{\circ}[/tex]
Calculating the heat capacity of this chunk of metal:
Using formula:
[tex]C_m=\frac{Q_m}{T_0-T_1}\\[/tex]
[tex]=\frac{4.184 \times 10^3}{100 -24}\\\\=\frac{4.184 \times 10^3}{76}\\\\=55.05 \ \frac{J}{K}[/tex]