Answer:
[tex]Pr = \frac{1}{2}[/tex]
Step-by-step explanation:
Given
[tex]S = \{1,2,3,4,5,6\}[/tex] --- the faces of the dice
[tex]n(S) = 6[/tex]
Required
Pr(Multiple of 8)
The multiples of 8 in the given dataset are:
[tex]Multiples = \{1.,2,4\}[/tex]
[tex]n(Multiples) = 3[/tex]
So, we have:
[tex]Pr = \frac{n(Multiples)}{n(S)}[/tex]
[tex]Pr = \frac{3}{6}[/tex]
Simplify
[tex]Pr = \frac{1}{2}[/tex]
