Respuesta :
Answer:
0.0462 ± 2.131(0.01565)
Step-by-step explanation:
The confidence interval for the slope, :
Slope Coefficient = 0.0462
Slope Coefficient ± Margin of error
Margin of Error = Tcritical * standard error
Standard Error (rotation) = 0.01565
We use T distribution, because sample size is small ; n = 16
Tcritical at 95% ; df = n - 1 = 16 - 1 = 15
Tcritical(0.05, 15) = 2.131
Hence,
Margin of Error = 2.131(0.01565)
Slope Coefficient for rotation = 0.0462
95% Confidence interval :
0.0462 ± 2.131(0.01565)
The 95% confidence interval for the slope of the regression line is 0.0462 ± 0.0333 or (0.01284, 0.07955)
What is the margin of error?
The probability or the chances of error while choosing or calculating a sample in a survey is called the margin of error.
Slope coefficient = 0.0462
Slope coefficient ± Margin of error
The margin of error will be given as
[tex]\rm Margin \ of \ error = T_{critical} \times standard \ error[/tex]
Standard error = 0.01565
We use T distribution because the sample size is small
[tex]\rm n = 16 \\\\T_{critical} \ at \ 95\% \ ; df = n-1 = 16- 1 = 15\\\\T_{critical} \ (0.05, 15) = 2.131[/tex]
Then we have
Margin of error = 2.131 × 0.01565
Margin of error = 0.0333
Then the 95% confidence interval will be
0.0462 ± 0.0333
More about the margin of error link is given below.
https://brainly.com/question/6979326