A waiter in a restaurant has eight booths in his station. How many different arrangements are possible for the hostess to seat customers at the waiter’s booths if order is important?

Respuesta :

Answer:

8 seats

Step-by-step explanation:

n = 8 ---booths

r = 1 --- hostess

Order is required

Important Order? We solve using permutation.

nPr = n!/(n - r)!

So we have:

8p1 = 8!/(8 - 1)!

IF we do the math correctly, we get this:

8p1 = 8/7!

Finally let's expand to come up with the solution.

8p1 = 8 x 7/7

8p1 = 8

So the answer is 8!

I hope this helps! Have a good day (PLS GIVE BRAINLIEST)

There are 8 types of different arrangements possible for the hostess to seat customers at the waiter’s booths if order is important.

What is Permutation and Combination ?

The various ways in which objects from a set may be selected, generally without replacement, to form subsets. This selection of subsets is called a permutation when the order of selection is a factor, a combination when order is not a factor.

Total number of booths = 8

To determine we will use the generalized expression

How many ways can you arrange 'r' from a set of 'n' if the order matters

P(n,r) = n! / (n-r)!

P(8,1) = 8!/ (8-1)!

= 8!/7!

= 8

So there are 8 types of different arrangements possible for the hostess to seat customers at the waiter’s booths if order is important.

To know more about Permutation and Combination

https://brainly.com/question/9283678

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