Answer:
87 metres
Step-by-step explanation:
The perimeter of the parking lot is 286 metres, while it is 56m in width.
The formula for the perimeter of a rectangle is:
[tex]P = 2(l+w)\\P = 2l + 2w[/tex]
with l and w as the the length and width, respectively.
The problem has two givens, perimeter and width.
[tex]286 = 2l + 2w\\286 = 2l + 2(56)\\286 - 112 = 2l\\174 = 2l\\\frac{174}{2} = l\\l=87[/tex]
The length of the lot is 87 meters.
