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Rhombus ABCD has a diagonal BD¯¯¯¯¯.

m∠ADB=(4x−12)°

m∠CDB=(3x+6)°

What is the m∠ADC ?

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Respuesta :

leoistired

Answer:

Angle ADC = 7x - 6°

Step-by-step explanation:

4x - 12 + 3x + 6 = 7x - 6

mhanifa

Answer:

  • 120°

Step-by-step explanation:

Diagonal BD of a given rhombus is angle bisector of ∠ADC, so:

  • m∠ADB = m∠CDB

Substitute the values and solve for x:

  • 4x - 12 = 3x + 6
  • 4x - 3x = 6 + 12
  • x = 18

Find the value of ∠ADC:

  • m∠ADC = 2(4*18 - 12) = 120°

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