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A bag contains five red marbles, two orange marbles, one yellow marble, and two green marbles. Two marbles are drawn from the bag. What is the approximate probability one of the chosen marbles is orange and one of the chosen marbles is green? 0.02222 0.04444 0.08889 0.13333

Respuesta :

Answer:B .04444

Step-by-step explanation: Edg

The probability of drawing an orange and a green marble is P = 0.08889

How to find the probability?

Let's assume that the first marble drawn is orange.

The probability of drawing an orange marble is equal to the quotient between the number of orange marbles and the total number of marbles on the bag, so the probability for this first event is:

p = 2/(5 + 2 + 1 + 2) = 2/10 = 1/5

Then we need to draw a green one, but notice that we already drew a marble, so now the total number of marbles is 9, then the probability will be:

q = 2/9

The joint probability is the product of these two, and we also need to add a factor of 2, because we also need to take in consideration the case where the first marble is green and the second is orange, then we will get:

P = 2*(1/5)*(2/9) = 0.08889

We can see that the correct option is the third one.

If you want to learn more about probability:

https://brainly.com/question/25870256

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