John has a bag of red and blue marbles. John chooses 2 marbles without replacing the first. Let A be the event where the first marble chosen
is red. Let B be the event where the second marble chosen is blue.

John has a bag of red and blue marbles John chooses 2 marbles without replacing the first Let A be the event where the first marble chosen is red Let B be the class=

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The answer is D. (The last one).

The conditional probability of an event depends on the occurrence of another event. The correct option is C.

What is Bayes' Theorem?

The conditional probability of an event depending on the occurrence of another event is equal to the likelihood of the second event given the first event multiplied by the probability of the first event, according to Bayes' Theorem.

Suppose that there are two events A and B. Then suppose the conditional probability is:

P(A|B) = probability of occurrence of A given B has already occurred.

P(B|A) = probability of occurrence of B given A has already occurred.

Then, according to Bayes' theorem, we have:

[tex]\rm P(A|B) = \dfrac{P(B|A)P(A)}{P(B)}[/tex]

(assuming the P(B) is not 0)

Given John has a bag of red and blue marbles. John chooses 2 marbles without replacing the first. Let A be the event where the first marble chosen

is red. Let B be the event where the second marble chosen is blue. Therefore, the Probability P(B|A)=0.6 is described as the probability of choosing a blue marble after a red marble has been removed is 0.6.

Hence, the correct option is C.

Learn more about Bayes' Theorem:

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