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Assuming the vertical sensitivity control is set to 0.5 volts per division, and the timebase control is set to 2.5 ms per division, calculate the amplitude of this sine wave in volts peak

Assuming the vertical sensitivity control is set to 05 volts per division and the timebase control is set to 25 ms per division calculate the amplitude of this class=

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Answer:

Amplitude of sine wave in volts peak = 2.25 V

Explanation:

Given:

Vertical sensitivity control = 0.5 volts per division

Time base control = 2.5 ms per division

Find:

Amplitude of sine wave in volts peak

Computation:

Amplitude of sine wave in volts peak = 4¹/₂[volts per division]

Amplitude of sine wave in volts peak = 4¹/₂[0.5]

Amplitude of sine wave in volts peak = 4.5[0.5]

Amplitude of sine wave in volts peak = 2.25 V

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