Answer: The enthalpy change during this reaction is 77505.56 J.
Explanation:
Given: [tex]T_{1} = 14^{o}C[/tex], [tex]T_{2} = 87^{o}C[/tex]
Mass = 254 g, Specific heat = [tex]4.18 J/g^{o}C[/tex]
Formula used to calculate the enthalpy change is as follows.
[tex]q = m \times C \times (T_{2} - T_{1})[/tex]
where,
q = enthalpy change
m = mass of substance
C = specific heat capacity
[tex]T_{1}[/tex] = initial temperature
[tex]T_{2}[/tex] = final temperature
Substitute the values into above formula as follows.
[tex]q = m \times C \times (T_{2} - T_{1})\\= 254 g \times 4.18 J/g^{o}C \times (87 - 14)^{o}C\\= 77505.56 J[/tex]
Thus, we can conclude that the enthalpy change during this reaction is 77505.56 J.
