Answer: The concentration of hydrogen ions for this solution is [tex]1.99 \times 10^{-3}[/tex].
Explanation:
Given: pOH = 11.30
The relation between pH and pOH is as follows.
pH + pOH = 14
pH + 11.30 = 14
pH = 14 - 11.30
= 2.7
Also, pH is the negative logarithm of concentration of hydrogen ions.
[tex]pH = - log [H^{+}][/tex]
Substitute the values into above formula as follows.
[tex]pH = -log [H^{+}]\\2.7 = -log [H^{+}]\\conc. of H^{+} = 1.99 \times 10^{-3}[/tex]
Thus, we can conclude that the concentration of hydrogen ions for this solution is [tex]1.99 \times 10^{-3}[/tex].