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3. How many moles of NaCl are present in 6000. La 1.5 M NaCl solution?
A.9.0

B.9.0 x 10^3 moles

C.4.0 x 10^8 moles​

Respuesta :

Cricetus

Answer:

Option A (9.0) is the correct alternative.

Explanation:

The given values are:

Molarity,

= 1.5 M

Volume,

= 6000 mL

or,

= 6 L

As we know,

⇒ [tex]Molarity=\frac{Moles}{Volume}[/tex]

or,

⇒ [tex]The \ moles \ of \ NaCl=Molarity\times Volume[/tex]

By putting the values, we get

                                     [tex]=1.5\times 6[/tex]

                                     [tex]=9 \ mol[/tex]

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