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In an electric resistance of 20 ohms, if the current intensity passing through it
is doubled, its value becomes ........ ohms.
b. 20
d. 40
a. 10
c. 30​

Respuesta :

onyebuchinnaji

Answer:

a.  10 ohms.

Explanation:

Given;

first electrical resistance, r₁ = 20 ohms

let the first current through the circuit = I₁

let the second current through the circuit, I₂ = 2I₁ (since it is doubled)

then, the new value of the resistance after doubling the current = r₂

the current intensity is given as;

[tex]\frac{dI}{dt} = I = \frac{v}{r} \\\\I_1r_1 = I_2r_2\\\\r_2 = \frac{I_1r_1}{I_2} \\\\r_2 = \frac{I_1 \times 20}{2I_1 } \\\\r_2 = 10 \ ohms[/tex]

Therefore, the new value of the resistance is 10 ohms.

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