A bacteria population is growing exponentially with a growth factor of 1/6 each hour. By what growth factor does the population change each half hour? Select all that apply

Using exponential function concepts, it is found that the change of the growth factor of the population each half hour is given by:
b. [tex]\sqrt{\frac{1}{6}}[/tex]
e. [tex]\left(\frac{1}{6}\right)^{0.5}[/tex]
An increasing exponential function is modeled by:
[tex]A(t) = A(0)(1 + r)^t[/tex]
In which:
In this problem, the growth factor of 1/6 each hour, hence, [tex]r = \frac{1}{6}[/tex], and:
[tex]A(t) = A(0)(1 + \frac{1}{6})^t[/tex]
For each half-hour, t = 0.5, hence the growth factor is of:
[tex]\left(\frac{1}{6}\right)^{0.5} = \sqrt{\frac{1}{6}}[/tex]
Hence, options b and e are correct.
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