Respuesta :

Answer:

[tex]RFM \: of \: methane \: = 16 \: g \\ 16 \: g \: are \: weighed \: by \: 1 \: mole \: of \: methane \\ 108.6 \: g \: are \: weighed \: by \: ( \frac{108.6}{16} \times 1) \: moles \\ = 6.7875 \: moles \: of \: methane \\ from \: the \: equation : \\ 1 \: mole \: of \: methane \: is \: formed \: by \: 2 \: moles \: of \: hydrogen \\ 6.7875 \: moles \: of \: methane \: will \: be \: produced \: by \: (6.7875 \times 2) \: moles \\ = 13.6 \: moles \: of \: hydrogen[/tex]