Answer:
About 400 times
Step-by-step explanation:
Given
[tex]n = 1060[/tex]
See attachment for spinner
Required
Determine the number of times an outcome of 1, 3 or 8 is expected
First, calculate the theoretical probability of 1, 3, or 8
This is calculated as:
[tex]Pr = P(1) + P(3) + P(8)[/tex]
The spinner is divided into 8 equal segments and each outcome appears once.
So, we have:
[tex]Pr = \frac{1}{8}+\frac{1}{8}+\frac{1}{8}[/tex]
Take LCM and add
[tex]Pr = \frac{1+1+1}{8}[/tex]
[tex]Pr = \frac{3}{8}[/tex]
So, the expected number of times (E) is:
[tex]E = Pr * n[/tex]
[tex]E = \frac{3}{8} * 1060[/tex]
[tex]E = \frac{3* 1060}{8}[/tex]
[tex]E = \frac{3180}{8}[/tex]
[tex]E = 397.5[/tex]
Approximate
[tex]E = 398[/tex]
This means about 400 times
