Answer:
Step-by-step explanation:
since cos ^2 = 1/4 then cos = 1/2
b/c cot is tan inverted, then cot = cos / sin
so we also know that [tex]\sqrt{3}[/tex]/2 will be sin for this same Ф
then
cot = (1/2) / ( [tex]\sqrt{3}[/tex]/2 )
cot = 1 / [tex]\sqrt{3}[/tex]
since Ф is in quad III
we know both parts of the fraction will be negative
cot = -1 / -[tex]\sqrt{3}[/tex]
but we would normally write that as a positive
