Answer:
There are 45 turns in the secondary coil.
Explanation:
Given that,
Input potential of the lamp, [tex]V_{in}=5\ V[/tex]
The output potential of the lamp, [tex]V_{out}=1.5\ V[/tex]
Number of turns in primary coil, [tex]N_P=150[/tex]
We need to find the number of turns needed on the secondary coil. We know that the ratio for a transformer is as follows :
[tex]\dfrac{V_{out}}{V_{in}}=\dfrac{N_s}{N_P}\\\\N_s=\dfrac{V_{out}N_P}{V_{in}}\\\\N_s=\dfrac{1.5\times 150}{5}\\\\N_s=45\[/tex]
So, there are 45 turns in the secondary coil.
