skinnbones30
contestada

please help!!!!!!!!
3x2 + x - 4 = 0

SELECT ALL THAT APPLY.



(x - 1)(3x + 4) = 0
(3x +2)(x - 6) = 0
(3x + 4)(x - 1) = 0
(x + 1)(3x - 4) = 0
(3x - 3)(3x - 4) = 0
(3x - 4)(x + 1) = 0

Respuesta :

Juanlopezisk18

all of the apply my math teacher always did that and all of them aways applied

nancygoyal

Answer:

(3x + 4)(x-1)=0

Step-by-step explanation:

It's a quadratic equation.

now you need to find two numbers such that when you multiply then you get -12 and when you add them you get +1

[tex]3x {}^{2} + x - 4 \\ 3x {}^{2} + 4x - 3x - 4 \\ x(3x + 4) - 1(3x + 4) \\ (3x + 4)(x - 1)[/tex]

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