Answer:
We will split the trapezoid into right angle triangle and rectangle
Traingle with base 3cm and height 10 - 6 = 4cm
Area of traingle
= [tex]\frac{1}{2}*base *height = \frac{1}{2} * 3 * 4 = 6cm^{2}[/tex]
Area of rectangle with sides 6cm and 3cm
=[tex]6 * 3 = 18cm^{2}[/tex]
Therefore, area of the trapezoid
= [tex]6+18 = 24cm^{2}[/tex]
Area of the semi circle with radius 3/2 = 1.5cm
= [tex]\frac{1}{2}\pi r^{2} = \frac{1*\pi *1.5*1.5}{2} = 1.125\pi cm^{2}[/tex]
[tex]Total area = 24 + 1.125\pi =27.53cm^{2}[/tex]
