Answer:
[tex]900\ \text{in}^2[/tex] Disagree
Step-by-step explanation:
[tex]b[/tex] = Length of side of base = 18 in
[tex]h[/tex] = Height of each triangle = 25 in
Lateral area of the pyramid is
[tex]A=\dfrac{4hb}{2}=2hb[/tex]
[tex]\Rightarrow A=2\times 25\times 18[/tex]
[tex]\Rightarrow A=900\ \text{in}^2[/tex]
The actual lateral area of the pyramid is [tex]900\ \text{in}^2[/tex] so, I disagree with Bella.
