Answer:
[tex]h(x) = -4(x - 2)(x + 2)[/tex]
Step-by-step explanation:
Given
[tex]h(x) = -4(x - 2)(x + 2)[/tex]
[tex]h(x) = -2(2x^2 - 8)[/tex]
[tex]h(x) = -4(x^2 - 4)[/tex]
[tex]h(x) = -4x^2 + 16[/tex]
Required
Which shows the zeros of h(x)
To determine the zeros of a function, the function must be written as:
[tex]h(x) = n(x \± a)(x \± b)[/tex]
Where
[tex]n \ne 0[/tex]
[tex]\± a,\± b[/tex] are the zeros
Of options (a) to (d), only (a) is written in the form:
[tex]h(x) = n(x \± a)(x \± b)[/tex]
i.e.
[tex]h(x) = -4(x - 2)(x + 2)[/tex]
Other options do not show the zeros
