Answer: There are 0.006 moles of acid in the flask.
Explanation:
Given: [tex]V_{1}[/tex] = 21.35 mL, [tex]M_{1}[/tex] = 0.150 M
[tex]V_{2}[/tex] = 25.0 mL, [tex]M_{2}[/tex] = ?
Formula used to calculate molarity of [tex]H_{2}SO_{4}[/tex] is as follows.
[tex]M_{1}V_{1} = M_{2}V_{2}[/tex]
Substitute the values into above formula as follows.
[tex]M_{1}V_{1} = M_{2}V_{2}\\0.15 M \times 21.35 mL = M_{2} \times 25.0 mL\\M_{2} = 0.1281 M[/tex]
As molarity is the number of moles of a substance present in a liter of solution.
Total volume of solution = [tex]V_{1} + V_{2}[/tex]
= 21.35 mL + 25.0 mL
= 46.36 mL (1 mL = 0.001 L)
= 0.04636 L
Therefore, moles of acid required are calculated as follows.
[tex]Molarity = \frac{no. of moles}{Volume (in L)}\\0.1281 M = \frac{no. of moles}{0.04635 L}\\no. of moles = 0.006 mol[/tex]
Thus, we can conclude that there are 0.006 moles of acid in the flask.
