Why can V-1 be written as an integer, but V1 cannot? (please look at photo)

Answer:
This is because the cube root of -1 gives a real number while the square root gives a complex number root value which we cannot write as an integer
Step-by-step explanation:
This is because, -1 raised to the power of 3 will give -1
However, -1 does not have any real root
Take for example, the square of -1 is 1
Hence the square root of -1 is not a real number which we can write as integer but a complex number which is not real