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What is the difference quotient of the function, g(a) = StartFraction 8 minus a Over 4 EndFraction?
PLEASE HELP

Respuesta :

Given:

The function is:

[tex]g(a)=\dfrac{8-a}{4}[/tex]

To find:

The difference quotient of the function.

Solution:

Formula for difference quotient of the function f(x) is:

[tex]DQ=\dfrac{f(x+h)-f(x)}{h}[/tex]

We have,

[tex]g(a)=\dfrac{8-a}{4}[/tex]

The difference quotient of the function g(a) is:

[tex]DQ=\dfrac{g(a+h)-g(a)}{h}[/tex]

[tex]DQ=\dfrac{\dfrac{8-(a+h)}{4}-\dfrac{8-a}{4}}{h}[/tex]

[tex]DQ=\dfrac{\dfrac{8-a-h-8+a}{4}}{h}[/tex]

[tex]DQ=\dfrac{-h}{4h}[/tex]

[tex]DQ=-\dfrac{1}{4}[/tex]

Therefore, the difference quotient of the given function is [tex]-\dfrac{1}{4}[/tex].

grossa

Answer:

They are right, It is -1/4. The second one.

Step-by-step explanation:

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