i am unsure can anyone help

Step-by-step explanation:
B. 20 only
hope it helps.
Answer:
[tex](6x + 1) = {(x - 9)}^{2} \\ {x}^{2} - 18x + 81 - 6x - 1 = {x}^{2} - 24x + 80 = 0 \\ x 1= \frac{24 + \sqrt{256} }{2 \times 1} = \frac{24 + 16}{2} = 20 \\ x 1= \frac{24 - \sqrt{256} }{2 \times 1} = \frac{24 - 16}{2} = 4[/tex]