Answer:[tex]1.95\times 10^5\ N/C[/tex]
Explanation:
Given
The charge per unit area on the plate is [tex]\sigma =3.47\times 10^{-6}\ C/m^2[/tex]
Electric for a infinitely large plane is given by
[tex]E=\dfrac{\sigma }{2\epsilon_o}[/tex]
Therefore, electric field at a point 2.4 m from the plane is
[tex]\Rightarrow E=\dfrac{3.47\times 10^{-6}}{2\times 8.854\times 10^{-12}}\\\\\Rightarrow E=0.195\times 10^6\ N/C[/tex]
