Answer:
n △JKL, segment KL is the leg opposite ∠J and segment KL is the leg adjacent to ∠J.
Step-by-step explanation:
Given
See attachment for [tex]\triangle JKL[/tex]
Required
Complete the blanks
From the question. we understand that [tex]\angle J[/tex] is the point of reference.
From the attached figure of [tex]\triangle JKL[/tex]
Segment KL is opposite to [tex]\angle J[/tex]
Segment JL is adjacent to [tex]\angle J[/tex]
