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Jared bought 7 cans of paint. A can of red paint costs $3.75. A can of black paint costs $2.75. Jared spent $22.25 in all. How many cans of black (b) and how many cans of red (r) did he buy? r+b=7 3.75r+2.75b=22.25 [?] red [ black Enter​

Jared bought 7 cans of paint A can of red paint costs 375 A can of black paint costs 275 Jared spent 2225 in all How many cans of black b and how many cans of r class=

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clarch19

Answer:

b = 4

r = 3

Step-by-step explanation:

r + b = 7

solve for 'r' to get r = 7-b

now substitute '7-b' for r in the second equation:

3.75(7-b) + 2.75b = 22.25

26.25 - 3.75b + 2.75b = 22.25

-b = -4

b = 4

r = 3

lillianguimond

Answer: Jared bougth 4 things of black paint and 3 cans of red paint

Step-by-step explanation:

3 * 3.75 = 11.25

4 * 2.75 = 11

togther these two coe out to equaling 22.25

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