Answer:
[tex]d=9.5g/L[/tex]
Explanation:
Hello there!
In this case, according to the given information, it i possible for us to calculate the density of this gas via the ideal gas equation, according to the following setup:
[tex]PV=nRT\\\\P=\frac{mRT}{V*MM} \\\\\frac{m}{V}=d=\frac{P*MM}{RT}[/tex]
Thus, we plug in the variables (pressure in atm and temperature in K) to obtain:
[tex]d=\frac{113.6368atm*2.02g/mol}{0.08206\frac{atm*L}{mol*K}*(21+273)K} \\\\d=9.5g/L[/tex]
Regards!
