Answer:
The answer is "19.77%"
Step-by-step explanation:
Given:
[tex]\mu = 19.7\\\\ \sigma = 2\\\\\to P(x >21.4 ) = 1 - P(x< 21.4)\\\\[/tex]
[tex]= 1 - [\frac{P(x -\mu)}{ \sigma }< \frac{(21.4-19.7)}{2}]\\\\= 1 - P(z < 0.85)\\\\= 1 - 0.8023\\\\=0.1977\\\\=19.77\%[/tex]