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The area vector of a square loop of 5 turns of a conductor each with side length of 0.2 m carrying a current of 2 A is antiparallel to a uniform magnetic field of 50.0 T in which it lies. Question 5. The magnitude and direction of the total magnetic moment is ……to the area vector.

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okpalawalter8

Answer:

[tex]M= 0.4 Am^2[/tex]

Explanation:

From the question we are told that:

Number of turns  [tex]N=5[/tex][tex]N=5[/tex]

Conductor each with side length [tex]L=0.2m[/tex]

Current [tex]I=2A[/tex]

Magnetic field  [tex]B=50.0T[/tex]

Generally the equation for the total magnetic moment  M is mathematically given by

[tex]M = current * area[/tex]

[tex]M= I * A[/tex]

[tex]M = 2 * (5* 0.2*0.2)[/tex]  

[tex]M = 2 * 0.2[/tex]

[tex]M= 0.4 Am^2[/tex]

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