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Two harmonic waves moving in the same direction are described by y1(x,t)=10.2sin(4x-700t) and y2(x,t)=10.2sin(4x-700t-7.9). What is the amplitude of the resultant wave at interference

Respuesta :

Answer:

14.42 units

Explanation:

The waves are given as follows :

[tex]y_1(x,t)=10.2\sin(4x-700t)\\\\y_2(x,t)=10.2\sin(4x-700t-7.9)[/tex]

We need to find the amplitude of the resultant wave at interference. Let it be A. So,

[tex]A=\sqrt{10.2^2+10.2^2} \\\\=14.42\ units[/tex]

So, the amplitude of the resultant wave is equal to 14.42 units.

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