The solution to the considered equation -12x^2 -x + 4 = 0 is x = -4 and x = 2 (the points where the curve of f(x) = -12x^2 -x + 4 touches x-axis).
What is x-intercept of a function?
The x-intercept of a function of variable x ( y = f(x) ) form is an intersection fo the x-axis and the curve of the function.
The x-intercept for a function y = f(x) is a solution to the equation f(x) = 0 becuase at that value of x, the function f(x) lies on x-axis, where y is 0. Values of x-intercept for a function f(x) are also called roots or solution of f(x) = 0 equation.
So, if we take:
[tex]f(x) = -12x^2 -x + 4[/tex]
then, the x-intercept for a function y = f(x) is a solution to the equation f(x) = 0, which is the equation [tex]-12x^2 -x + 4 = 0[/tex]
The x-intercept is visible from the graph being at x = -4 and x = 2
Thus, the solution to the considered equation [tex]-12x^2 -x + 4 = 0[/tex] is x = -4 and x = 2
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