Respuesta :
Answer:
the frequency of the second harmonic of the pipe is 425 Hz
Explanation:
Given;
length of the open pipe, L = 0.8 m
velocity of sound, v = 340 m/s
The wavelength of the second harmonic is calculated as follows;
L = A ---> N + N--->N + N--->A
where;
L is the length of the pipe in the second harmonic
A represents antinode of the wave
N represents the node of the wave
[tex]L = \frac{\lambda}{4} + \frac{\lambda}{2} + \frac{\lambda}{4} \\\\L = \lambda[/tex]
The frequency is calculated as follows;
[tex]F_1 = \frac{V}{\lambda} = \frac{340}{0.8} = 425 \ Hz[/tex]
Therefore, the frequency of the second harmonic of the pipe is 425 Hz.
The frequency of the second harmonic of the pipe is 425 Hz.
What is the frequency?
Frequency is the number of oscillations per second in the sinusoidal wave.
Given is length of the open pipe, L = 0.8 m, and velocity of sound, v = 340 m/s
The wavelength of the second harmonic is represented as
L = A → N + N→N + N→A
where, L is the length of the pipe in the second harmonic, A represents antinode of the wave, N represents the node of the wave
Length = λ/4 +λ/2 +λ/4
Length = λ
The frequency is calculated
frequency = speed of light / wavelength
Put the values, we get
f = 340/0.80
f = 425 Hz
Therefore, the frequency of the second harmonic of the pipe is 425 Hz.
Learn more about frequency.
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