Answer:
74.88N
Explanation:
From the question,
F = ma................... Equation 1
Where F = force exerted on the ball, m = mass of the ball, a = acceleration
But,
v² = u²+2as.............. Equation 2
Where v = final velocity, u = initial velocity, s = distance.
Given: v = 12 m/s, u = 0 m/s (from rest), s = 5.0 m
Substitute into equation 2 and solve for a
12² = 0²+2×a×5
144 = 10a
10a = 144
a = 144/10
a = 14.4 m/s²
Also Given: m = 5.2 kg,
Substitute into equation 1
F = 5.2×14.4
F = 74.88 N
Hence the force exerted on the ball is 74.88 N
