Peyton is going to invest $440 and leave it in an account for 5 years. Assuming the
interest is compounded annually, what interest rate, to the nearest tenth of a percent,
would be required in order for Peyton to end up with $520?

Respuesta :

Answer:

The required interest rate would be of 3.4% a year.

Step-by-step explanation:

The amount of money earned in compound interest, after t years, is given by:

[tex]P(t) = P(0)(1+r)^t[/tex]

In which P(0) is the initial investment and r is the interest rate, as a decimal.

Peyton is going to invest $440 and leave it in an account for 5 years.

This means that [tex]P(0) = 440, t = 5[/tex]

So

[tex]P(t) = P(0)(1+r)^t[/tex]

[tex]P(t) = 440(1+r)^5[/tex]

What interest rate, to the nearest tenth of a percent, would be required in order for Peyton to end up with $520?

This is r for which P(t) = 520. So

[tex]P(t) = 440(1+r)^5[/tex]

[tex](1+r)^5 = \frac{520}{440}[/tex]

[tex]\sqrt[5]{(1+r)^5} = \sqrt[5]{\frac{52}{44}}[/tex]

[tex]1 + r = (\frac{52}{44})^{\frac{1}{5}}[/tex]

[tex]1 + r = 1.034[/tex]

Then

[tex]r = 1.034 - 1 = 0.034[/tex]

The required interest rate would be of 3.4% a year.